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Difference between revisions of "FIND from WORLD"

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<div class=ans>
 
<div class=ans>
 
pp.pprint(list(db.world.find({},{"name":1,"continent":1,"population":1,"_id":0})))
 
pp.pprint(list(db.world.find({},{"name":1,"continent":1,"population":1,"_id":0})))
 +
</div>
 +
</div>
 +
 +
 +
<div class=q data-lang="py3">
 +
<p class=strong>Show the name for the countries that have a population of at least 200 million. 200 million is 200000000, there are eight zeros.</p>
 +
<pre class=def>
 +
pp.pprint(list(
 +
    db.world.find(
 +
      {"population":{"$gt":200000000}},
 +
      {"name":1, "_id":0}
 +
    )
 +
))
 +
</pre>
 +
<div class=ans>
 +
pp.pprint(list(db.world.find({"population":{"$gt":200000000}},{"name":1, "_id":0})))
 +
</div>
 +
</div>
 +
 +
<div class=q data-lang="py3">
 +
<p class=strong>Give the name and the per capita GDP for those countries with a population of at least 200 million.</p>
 +
[[AGGREGATE examples]] are available.
 +
<div class="hint" title="How to calculate per capita GDP">per capita GDP is the GDP divided by the population GDP/population</div>
 +
<pre class=def>
 +
pp.pprint(list(
 +
    db.world.aggregate([
 +
        {"$match":{"population":{"$gt":200000000}}},
 +
        {"$project":{"name":1, "per capita GDP":{"$divide":["$gdp","$population"]}, "_id":0}}
 +
    ])
 +
))
 +
</pre>
 +
</div>
 +
 +
<div class=q data-lang="py3">
 +
<p class=strong>Show the name and population in millions for the countries of the continent 'South America'. Divide the population by 1000000 to get population in millions.</p>
 +
<pre class=def>
 +
pp.pprint(list(
 +
    db.world.aggregate([
 +
        {"$match":{"continent":{"$eq":"South America"}}},
 +
        {"$project":{"name":1, "population in millions":{"$divide":["$population",1000000]}, "_id":0}}
 +
    ])
 +
))
 +
</pre>
 +
<div class=ans>
 +
pp.pprint(list(db.world.aggregate([{"$match":{"continent":{"$eq":"South America"}}},{"$project":{"name":1, "population in millions":{"$divide":["$population",1000000]}, "_id":0}}])))
 +
</div>
 +
</div>
 +
 +
<div class=q data-lang="py3">
 +
<p class=strong>Show the name and population for France, Germany, Italy</p>
 +
<pre class=def>
 +
pp.pprint(list(
 +
    db.world.aggregate([
 +
        {"$match":{"name":{"$in":["France", "Germany", "Italy"]}}},
 +
        {"$project":{"name":1, "population":1, "_id":0}}
 +
    ])
 +
))
 +
</pre>
 +
<div class=ans>
 +
pp.pprint(list(db.world.aggregate([{"$match":{"name":{"$in":["France", "Germany", "Italy"]}}},{"$project":{"name":1, "population":1, "_id":0}}])))
 +
</div>
 +
</div>
 +
 +
<div class=q data-lang="py3">
 +
<p class=strong>Show the countries which have a name that includes the word 'United'</p>
 +
<pre class=def>
 +
pp.pprint(list(
 +
    db.world.find(
 +
        {"name":{"$regex":"\s?United\s?"}},
 +
        {"name":1, "_id":0}
 +
    )
 +
))
 +
</pre>
 +
<div class=ans>
 +
pp.pprint(list(db.world.find({"name":{"$regex":"\s?United\s?"}},{"name":1, "_id":0})))
 +
</div>
 +
</div>
 +
 +
<div class=q data-lang="py3">
 +
Two ways to be big: A country is big if it has an area of more than 3 million sq km or it has a population of more than 250 million.
 +
<p class=strong>Show the countries that are big by area or big by population. Show name, population and area</p>
 +
<pre class=def>
 +
pp.pprint(list(
 +
    db.world.find(
 +
        {"$or":[{"area":{"$gt":3000000}},{"population":{"$gt":250000000}}]},
 +
        {"name":1,"population":1,"area":1,"_id":0}
 +
    )
 +
))
 +
</pre>
 +
<div class=ans>
 +
pp.pprint(list(db.world.find({"$or":[{"area":{"$gt":3000000}},{"population":{"$gt":250000000}}]},{"name":1,"population":1,"area":1,"_id":0})))
 +
</div>
 +
</div>
 +
 +
<div class=q data-lang="py3">
 +
USA and China are big in population <span class=strong>and</span> big by area. Exclude these countries.
 +
<p class=strong>Show the countries that are big by area or big by population but not both. Show name, population and area.</p>
 +
<pre class=def>
 +
pp.pprint(list(
 +
    db.world.find(
 +
        {"$or":[
 +
          {"area":{"$gt":3000000},"population":{"$lt":250000000}},
 +
          {"area":{"$lt":3000000},"population":{"$gt":250000000}}
 +
        ]},   
 +
        {"name":1,"population":1,"area":1,"_id":0}
 +
    )
 +
))
 +
</pre>
 +
<div class=ans>
 +
pp.pprint(list(db.world.find({"$or":[{"area":{"$gt":3000000},"population":{"$lt":250000000}},{"area":{"$lt":3000000},"population":{"$gt":250000000}}]},    {"name":1,"population":1,"area":1,"_id":0})))
 +
</div>
 +
</div>
 +
 +
<div class=q data-lang="py3">
 +
Show the name and population in millions and the GDP in billions for the countries of the continent 'South America'. Use the ROUND function to show the values to two decimal places.<br />
 +
Introducing [[MapReduce]]
 +
<div class=hint title='Millions and billions'>Divide by 1000000 (6 zeros) for millions. Divide by 1000000000 (9 zeros) for billions.</div>
 +
<p class=strong>For South America show population in millions and GDP in billions to 2 decimal places.</p>
 +
<pre class=def>
 +
from bson.code import Code
 +
temp = db.world.map_reduce(
 +
        query={"continent":"South America"},
 +
        map=Code("function(){emit(this.name,{'gdp':this.gdp,'pop':this.population});}"),
 +
        reduce=Code("""function(key, values){ return values} """),
 +
        finalize=Code("""function(k, v){
 +
              return {
 +
                  'pop in millions':Math.round(v['pop']*1000000)/1000000,
 +
                  'gdp in billions':Math.round(v['gdp']*1000000000)/1000000000
 +
              };
 +
          }
 +
        """),
 +
        out={"inline":1}
 +
)
 +
pp.pprint(temp['results']);
 +
</pre>
 +
<div class=ans>
 +
from bson.code import Code
 +
temp = db.world.map_reduce(query={"continent":"South America"},map=Code("function(){emit(this.name, {'gdp':this.gdp,'pop':this.population});}"),reduce=Code("""function(key, values){ return values} """),finalize=Code("""function(k, v){return {'pop in millions':Math.round(v['pop']*1000000)/1000000,'gdp in billions':Math.round(v['gdp']*1000000000)/1000000000};}"""),out={"inline":1})
 +
pp.pprint(temp['results']);
 +
</div>
 +
</div>
 +
 +
<div class=q data-lang="py3">
 +
Show the per-capita GDP for those countries with a GDP of at least one trillion (1000000000000; that is 12 zeros). Round this value to the nearest 1000.
 +
<p class=strong>Show per-capita GDP for the trillion dollar countries to the nearest $1000.</p>
 +
<pre class=def>
 +
from bson.code import Code
 +
temp = db.world.map_reduce(
 +
        map=Code("function(){if(this.gdp > 1000000000000)emit(this.name,{'gdp':this.gdp,'pop':this.population});}"),
 +
        reduce=Code("""function(key, values){ return values} """),
 +
        finalize=Code("""function(k, v){
 +
              return {'per-capita GDP':Math.round((v['gdp']/v['pop'])/1000)*1000};
 +
          }
 +
        """),
 +
        out={"inline":1}
 +
)
 +
pp.pprint(temp['results']);
 +
</pre>
 +
<div class=ans>
 +
from bson.code import Code
 +
temp = db.world.map_reduce(map=Code("function(){if(this.gdp > 1000000000000)emit(this.name,{'gdp':this.gdp,'pop':this.population});}"),reduce=Code("""function(key, values){ return values} """),finalize=Code("""function(k, v){
 +
return {'per-capita GDP':Math.round((v['gdp']/v['pop'])/1000)*1000};}"""),out={"inline":1})
 +
pp.pprint(temp['results']);
 +
</div>
 +
</div>
 +
 +
== Harder Questions ==
 +
 +
<div class=q data-lang="py3">
 +
Find out more about <code>$cond</code> at [[AGGREGATE_examples]]
 +
<p class=strong>Show the name and the continent - but substitute Australasia for Oceania - for countries beginning with N.</p>
 +
<pre class=def>
 +
pp.pprint(list(
 +
    db.world.aggregate([
 +
        {"$match":{"name":{"$regex":"^N"}}},
 +
        {"$project":{
 +
            "name":1,
 +
            "continent":{"$cond":[{"$eq":["$continent","Oceania"]},"Australasia","$continent"]},
 +
            "_id":0
 +
        }}
 +
    ])
 +
))
 +
</pre>
 +
<div class=ans>
 +
pp.pprint(list(db.world.aggregate([{"$match":{"name":{"$regex":"^N"}}},{"$project":{"_id":0,"name":1,"continent":{"$cond":[{"$eq":["$continent","Oceania"]},"Australasia","$continent"]}}}])))
 +
</div>
 +
</div>
 +
 +
<div class=q data-lang="py3">
 +
Show the <b>name</b> and the <b>continent</b> but:<br/><br/>
 +
&nbsp;&nbsp;&nbsp;&nbsp;substitute <b>Eurasia</b> for <b>Europe</b> and <b>Asia</b>.<br/>
 +
&nbsp;&nbsp;&nbsp;&nbsp;substitute <b>America</b> - for each country in <b>North America</b> or <b>South America</b> or <b>Caribbean</b>.<br/><br/>Only show countries beginning with <b>A</b> or <b>B</b><br/>
 +
If you're struggling you may want to experiment with <code>$and</code>,<code>$or</code>, etc.
 +
<pre class=def>
 +
pp.pprint(list(
 +
    db.world.aggregate([
 +
        {"$match":{
 +
            "name":{"$regex":"^A|^B"}
 +
        }},
 +
        {"$project":{
 +
            "_id":0,
 +
            "name":1,
 +
            "continent": {
 +
                "$cond": [{
 +
                    "$or":[
 +
                        {"$eq":["$continent","Europe"]},
 +
                        {"$eq":["$continent","Asia"]}
 +
                    ]},"Eurasia",{
 +
                        "$cond": [
 +
                            {"$or":[
 +
                                {"$eq":["$continent","North America"]},
 +
                                {"$eq":["$continent","South America"]},
 +
                                {"$eq":["$continent","Caribbean"]}
 +
                            ]},"America","$continent"]}
 +
                ]}
 +
        }}
 +
    ])
 +
))
 +
</pre>
 +
<div class=ans>
 +
pp.pprint(list(
 +
    db.world.aggregate([
 +
        {"$match":{
 +
            "name":{"$regex":"^A|^B"}
 +
        }},
 +
        {"$project":{
 +
            "_id":0,
 +
            "name":1,
 +
            "continent": {
 +
                "$cond": [{
 +
                    "$or":[
 +
                        {"$eq":["$continent","Europe"]},
 +
                        {"$eq":["$continent","Asia"]}
 +
                    ]},"Eurasia",{
 +
                        "$cond": [
 +
                            {"$or":[
 +
                                {"$eq":["$continent","North America"]},
 +
                                {"$eq":["$continent","South America"]},
 +
                                {"$eq":["$continent","Caribbean"]}
 +
                            ]},"America","$continent"]}
 +
                ]}
 +
        }}
 +
    ])
 +
))
 +
</div>
 +
</div>
 +
 +
<div class=q data-lang="py3">
 +
Put the continents right...
 +
<br/><br/>
 +
&nbsp;&nbsp;&nbsp;&nbsp;<b>Oceania</b> becomes <b>Australasia</b><br/>
 +
&nbsp;&nbsp;&nbsp;&nbsp;Countries in <b>Eurasia</b> and <b>Turkey</b> go to <b>Europe/Asia</b><br/>
 +
&nbsp;&nbsp;&nbsp;&nbsp;<b>Caribbean</b> islands starting with '<b>B</b>' go to <b>North America</b>, other Caribbean islands go to <b>South America</b><br/>
 +
<br/><br/>
 +
<b>Show the name, the original continent and the new continent of all countries.</b>
 +
<pre class=def>
 +
pp.pprint(list(
 +
    db.world.aggregate([
 +
        {"$project":{
 +
            "_id":0,
 +
            "name":1,
 +
            "original": "$continent",
 +
            "new": {
 +
                "$cond": [
 +
                    {"$or":[
 +
                        {"$eq":["$continent","Eurasia"]},
 +
                        {"$eq":["$name","Turkey"]}
 +
                    ]},"Europe/Asia",{
 +
                        "$cond":[
 +
                            {"$eq":["$continent","Oceania"]},"Australasia",{
 +
                                "$cond":[
 +
                                    {"$and":[
 +
                                        {"$eq":["$continent","Caribbean"]},
 +
                                        {"$eq":[{"$substr":["$name",0,1]}, "B"]}
 +
                                    ]},"North America",{
 +
                                        "$cond":[
 +
                                            {"$and":[
 +
                                                {"$eq":["$continent","Caribbean"]},
 +
                                                {"$ne":[{"$substr":["$name",0,1]}, "B"]}
 +
                                            ]},"South America","$continent"
 +
                                        ]
 +
                                    }
 +
                                ]
 +
                            }
 +
                        ]
 +
                  }
 +
                ]
 +
            }
 +
        }}
 +
    ])
 +
))
 +
</pre>
 +
<div class=ans>
 +
pp.pprint(list(
 +
    db.world.aggregate([
 +
        {"$project":{
 +
            "_id":0,
 +
            "name":1,
 +
            "original": "$continent",
 +
            "new": {
 +
                "$cond": [
 +
                    {"$or":[
 +
                        {"$eq":["$continent","Eurasia"]},
 +
                        {"$eq":["$name","Turkey"]}
 +
                    ]},"Europe/Asia",{
 +
                        "$cond":[
 +
                            {"$eq":["$continent","Oceania"]},"Australasia",{
 +
                                "$cond":[
 +
                                    {"$and":[
 +
                                        {"$eq":["$continent","Caribbean"]},
 +
                                        {"$eq":[{"$substr":["$name",0,1]}, "B"]}
 +
                                    ]},"North America",{
 +
                                        "$cond":[
 +
                                            {"$and":[
 +
                                                {"$eq":["$continent","Caribbean"]},
 +
                                                {"$ne":[{"$substr":["$name",0,1]}, "B"]}
 +
                                            ]},"South America","$continent"
 +
                                        ]
 +
                                    }
 +
                                ]
 +
                            }
 +
                        ]
 +
                  }
 +
                ]
 +
            }
 +
        }}
 +
    ])
 +
))
 
</div>
 
</div>
 
</div>
 
</div>

Latest revision as of 10:34, 13 November 2015

#ENCODING
import io
import sys
sys.stdout = io.TextIOWrapper(sys.stdout.buffer, encoding='utf-16')
#MONGO
from pymongo import MongoClient
client = MongoClient()
client.progzoo.authenticate('scott','tiger')
db = client['progzoo']
#PRETTY
import pprint
pp = pprint.PrettyPrinter(indent=4)

Working with the world collection of countries

This tutorial introduces NoSQL using MonogDB and PyMongo under Python3.4. We will be using the find() command and comparison functions on the collection world which contains details of around 250 countries of the world:

FIND examples are available.


Observe the result of running a simple mongoDB command.

FIND name, continent, population FROM world

pp.pprint(list(
    db.world.find({},{
      "name":1,
      "continent":1,
      "population":1,
      "_id":0
    })
))

pp.pprint(list(db.world.find({},{"name":1,"continent":1,"population":1,"_id":0})))


Show the name for the countries that have a population of at least 200 million. 200 million is 200000000, there are eight zeros.

pp.pprint(list(
    db.world.find(
      {"population":{"$gt":200000000}},
      {"name":1, "_id":0}
    )
))

pp.pprint(list(db.world.find({"population":{"$gt":200000000}},{"name":1, "_id":0})))

Give the name and the per capita GDP for those countries with a population of at least 200 million.

AGGREGATE examples are available.

per capita GDP is the GDP divided by the population GDP/population
pp.pprint(list(
    db.world.aggregate([
        {"$match":{"population":{"$gt":200000000}}},
        {"$project":{"name":1, "per capita GDP":{"$divide":["$gdp","$population"]}, "_id":0}}
    ])
))

Show the name and population in millions for the countries of the continent 'South America'. Divide the population by 1000000 to get population in millions.

pp.pprint(list(
    db.world.aggregate([
        {"$match":{"continent":{"$eq":"South America"}}},
        {"$project":{"name":1, "population in millions":{"$divide":["$population",1000000]}, "_id":0}}
    ])
))

pp.pprint(list(db.world.aggregate([{"$match":{"continent":{"$eq":"South America"}}},{"$project":{"name":1, "population in millions":{"$divide":["$population",1000000]}, "_id":0}}])))

Show the name and population for France, Germany, Italy

pp.pprint(list(
    db.world.aggregate([
        {"$match":{"name":{"$in":["France", "Germany", "Italy"]}}},
        {"$project":{"name":1, "population":1, "_id":0}}
    ])
))

pp.pprint(list(db.world.aggregate([{"$match":{"name":{"$in":["France", "Germany", "Italy"]}}},{"$project":{"name":1, "population":1, "_id":0}}])))

Show the countries which have a name that includes the word 'United'

pp.pprint(list(
    db.world.find(
        {"name":{"$regex":"\s?United\s?"}},
        {"name":1, "_id":0}
    )
))

pp.pprint(list(db.world.find({"name":{"$regex":"\s?United\s?"}},{"name":1, "_id":0})))

Two ways to be big: A country is big if it has an area of more than 3 million sq km or it has a population of more than 250 million.

Show the countries that are big by area or big by population. Show name, population and area

pp.pprint(list(
    db.world.find(
        {"$or":[{"area":{"$gt":3000000}},{"population":{"$gt":250000000}}]},
        {"name":1,"population":1,"area":1,"_id":0}
    )
))

pp.pprint(list(db.world.find({"$or":[{"area":{"$gt":3000000}},{"population":{"$gt":250000000}}]},{"name":1,"population":1,"area":1,"_id":0})))

USA and China are big in population and big by area. Exclude these countries.

Show the countries that are big by area or big by population but not both. Show name, population and area.

pp.pprint(list(
    db.world.find(
        {"$or":[
          {"area":{"$gt":3000000},"population":{"$lt":250000000}},
          {"area":{"$lt":3000000},"population":{"$gt":250000000}}
        ]},    
        {"name":1,"population":1,"area":1,"_id":0}
    )
))

pp.pprint(list(db.world.find({"$or":[{"area":{"$gt":3000000},"population":{"$lt":250000000}},{"area":{"$lt":3000000},"population":{"$gt":250000000}}]}, {"name":1,"population":1,"area":1,"_id":0})))

Show the name and population in millions and the GDP in billions for the countries of the continent 'South America'. Use the ROUND function to show the values to two decimal places.
Introducing MapReduce

Divide by 1000000 (6 zeros) for millions. Divide by 1000000000 (9 zeros) for billions.

For South America show population in millions and GDP in billions to 2 decimal places.

from bson.code import Code
temp = db.world.map_reduce(
        query={"continent":"South America"},
        map=Code("function(){emit(this.name,{'gdp':this.gdp,'pop':this.population});}"), 
        reduce=Code("""function(key, values){ return values} """),
        finalize=Code("""function(k, v){
               return {
                   'pop in millions':Math.round(v['pop']*1000000)/1000000,
                   'gdp in billions':Math.round(v['gdp']*1000000000)/1000000000
               };
           }
        """),
        out={"inline":1}
)
pp.pprint(temp['results']);

from bson.code import Code temp = db.world.map_reduce(query={"continent":"South America"},map=Code("function(){emit(this.name, {'gdp':this.gdp,'pop':this.population});}"),reduce=Code("""function(key, values){ return values} """),finalize=Code("""function(k, v){return {'pop in millions':Math.round(v['pop']*1000000)/1000000,'gdp in billions':Math.round(v['gdp']*1000000000)/1000000000};}"""),out={"inline":1}) pp.pprint(temp['results']);

Show the per-capita GDP for those countries with a GDP of at least one trillion (1000000000000; that is 12 zeros). Round this value to the nearest 1000.

Show per-capita GDP for the trillion dollar countries to the nearest $1000.

from bson.code import Code
temp = db.world.map_reduce(
        map=Code("function(){if(this.gdp > 1000000000000)emit(this.name,{'gdp':this.gdp,'pop':this.population});}"), 
        reduce=Code("""function(key, values){ return values} """),
        finalize=Code("""function(k, v){
               return {'per-capita GDP':Math.round((v['gdp']/v['pop'])/1000)*1000};
           }
        """),
        out={"inline":1}
)
pp.pprint(temp['results']);

from bson.code import Code temp = db.world.map_reduce(map=Code("function(){if(this.gdp > 1000000000000)emit(this.name,{'gdp':this.gdp,'pop':this.population});}"),reduce=Code("""function(key, values){ return values} """),finalize=Code("""function(k, v){ return {'per-capita GDP':Math.round((v['gdp']/v['pop'])/1000)*1000};}"""),out={"inline":1}) pp.pprint(temp['results']);

Harder Questions

Find out more about $cond at AGGREGATE_examples

Show the name and the continent - but substitute Australasia for Oceania - for countries beginning with N.

pp.pprint(list(
    db.world.aggregate([
        {"$match":{"name":{"$regex":"^N"}}},
        {"$project":{
            "name":1,
            "continent":{"$cond":[{"$eq":["$continent","Oceania"]},"Australasia","$continent"]}, 
            "_id":0
        }}
    ])
))

pp.pprint(list(db.world.aggregate([{"$match":{"name":{"$regex":"^N"}}},{"$project":{"_id":0,"name":1,"continent":{"$cond":[{"$eq":["$continent","Oceania"]},"Australasia","$continent"]}}}])))

Show the name and the continent but:

    substitute Eurasia for Europe and Asia.
    substitute America - for each country in North America or South America or Caribbean.

Only show countries beginning with A or B
If you're struggling you may want to experiment with $and,$or, etc.

pp.pprint(list(
    db.world.aggregate([
        {"$match":{
            "name":{"$regex":"^A|^B"}
        }},
        {"$project":{
            "_id":0,
            "name":1,
            "continent": {
                "$cond": [{
                    "$or":[ 
                        {"$eq":["$continent","Europe"]},
                        {"$eq":["$continent","Asia"]}
                    ]},"Eurasia",{
                        "$cond": [
                            {"$or":[ 
                                {"$eq":["$continent","North America"]},
                                {"$eq":["$continent","South America"]},
                                {"$eq":["$continent","Caribbean"]}
                            ]},"America","$continent"]}
                ]}
        }}
    ])
))

pp.pprint(list(

   db.world.aggregate([
       {"$match":{
           "name":{"$regex":"^A|^B"}
       }},
       {"$project":{
           "_id":0,
           "name":1,
           "continent": {
               "$cond": [{
                   "$or":[ 
                       {"$eq":["$continent","Europe"]},
                       {"$eq":["$continent","Asia"]}
                   ]},"Eurasia",{
                       "$cond": [
                           {"$or":[ 
                               {"$eq":["$continent","North America"]},
                               {"$eq":["$continent","South America"]},
                               {"$eq":["$continent","Caribbean"]}
                           ]},"America","$continent"]}
               ]}
       }}
   ])

))

Put the continents right...

    Oceania becomes Australasia
    Countries in Eurasia and Turkey go to Europe/Asia
    Caribbean islands starting with 'B' go to North America, other Caribbean islands go to South America


Show the name, the original continent and the new continent of all countries.

pp.pprint(list(
    db.world.aggregate([
        {"$project":{
            "_id":0,
            "name":1,
            "original": "$continent",
            "new": {
                "$cond": [
                    {"$or":[ 
                        {"$eq":["$continent","Eurasia"]},
                        {"$eq":["$name","Turkey"]}
                    ]},"Europe/Asia",{
                        "$cond":[
                            {"$eq":["$continent","Oceania"]},"Australasia",{
                                "$cond":[
                                    {"$and":[
                                        {"$eq":["$continent","Caribbean"]},
                                        {"$eq":[{"$substr":["$name",0,1]}, "B"]}
                                    ]},"North America",{
                                        "$cond":[
                                            {"$and":[
                                                {"$eq":["$continent","Caribbean"]},
                                                {"$ne":[{"$substr":["$name",0,1]}, "B"]}
                                            ]},"South America","$continent"
                                        ]
                                    }
                                ]
                            }
                        ]
                   }
                ]
            }
        }}
    ])
))

pp.pprint(list(

   db.world.aggregate([
       {"$project":{
           "_id":0,
           "name":1,
           "original": "$continent",
           "new": {
               "$cond": [
                   {"$or":[ 
                       {"$eq":["$continent","Eurasia"]},
                       {"$eq":["$name","Turkey"]}
                   ]},"Europe/Asia",{
                       "$cond":[
                           {"$eq":["$continent","Oceania"]},"Australasia",{
                               "$cond":[
                                   {"$and":[
                                       {"$eq":["$continent","Caribbean"]},
                                       {"$eq":[{"$substr":["$name",0,1]}, "B"]}
                                   ]},"North America",{
                                       "$cond":[
                                           {"$and":[
                                               {"$eq":["$continent","Caribbean"]},
                                               {"$ne":[{"$substr":["$name",0,1]}, "B"]}
                                           ]},"South America","$continent"
                                       ]
                                   }
                               ]
                           }
                       ]
                  }
               ]
           }
       }}
   ])

))