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Difference between revisions of "AGGREGATE Movies Tutorial"

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</pre>
 
</pre>
 
<pre class=ans>db.movies.aggregate([
 
<pre class=ans>db.movies.aggregate([
     {$match:{
+
     {$match:{  
 
         title:'Casablanca'
 
         title:'Casablanca'
 
     }}
 
     }}

Revision as of 20:42, 17 October 2016

Investigating the Movie Database

The movie database includes thousands of movies with documents such as:

{
	"_id" : 10522,
	"title" : "Alien",
	"yr" : 1979,
	"director" : "Ridley Scott",
	"budget" : 11000000,
	"gross" : 104931801,
	"cast" : [
		"Tom Skerritt",
		"Sigourney Weaver",
		"Veronica Cartwright",
		"Harry Dean Stanton",
		"John Hurt",
		"Ian Holm",
		"Yaphet Kotto"
	]
}

Casablanca

Show the details of the movie Casablanca

db.movies.aggregate([
    {$match:{
        title:'Alien'
    }},
]).pretty()
db.movies.aggregate([
    {$match:{ 
        title:'Casablanca'
    }}
]).pretty()

Tom Hanks

You can use the match operator on listed items like cast. As there is an index on cast these queries operate quickly and do not have to scan the entire collection.

Show the title and year of the 10 most recent Tom Hanks movies - show the most recent first.
db.movies.aggregate([
    {$match:{
        cast:'Harrison Ford'
    }},
    {$project:{_id:0,title:1}
]).pretty()
db.movies.aggregate([
    {$match:{
        cast:'Tom Hanks'
    }},
    {$project:{title:1,yr:1,_id:0}},
    {$sort:{yr:-1}},
    {$limit:10}
])