AGGREGATE Tutorial
Contents
- 1 Country Profile
- 2 Per Capita GDP
- 3 Population Density in South America
- 4 Population Density for "V"
- 5 Population in millions
- 6 Population density
- 7 Continents by area
- 8 Big Continents
- 9 First and last country by continent
- 10 Countries beginning with...
- 11 Harder Questions
- 12 Messing with continent names
- 13 Messing with continent names 2
- 14 Messing with continent names 3
- 15 Messing with continent names 4
Country Profile
For these questions you should use aggregate([]) on the collection world
You may find these AGGREGATE examples useful.
Per Capita GDP
Give the name and the per capita GDP for those countries with a population of at least 200 million.
per capita GDP is the GDP divided by the population.
db.world.aggregate([
{$match:{
population:{$gte:250000000}
}},
{$project:{
_id:0,
name:1,
"per capita GDP": {$divide: ['$gdp',1000000]}
}}
])
Population Density in South America
Give the name and the population density of all countries in South America.
population density is the population divided by the area
Use a $match. {"area":{"$ne":0}}
db.world.aggregate([
{$match:{continent:'Asia'}},
{$project:{
_id:0,
name:1,
density: {$divide: ["$population","$area"]}
}},
])
db.world.aggregate([
{$match:{continent:'South America'}},
{$project:{
_id:0,
name:1,
density: {$divide: ["$population","$area"]}
}}
])
Population Density for "V"
Give the name and the population density of all countries with name after V in the alphabet.
Note that because Vatican City (with area 0) is in Europe you will get a divide by zero error unless you filter first.
Use a $match. {$match:{area:{"$ne":0}}}
db.world.aggregate([
{$match:{name:{$gt:'V'}}},
{$project:{
_id:0,
name:1,
area:1
}},
])
db.world.aggregate([
{$match:{name:{$gt:'V'}}},
{$match:{area:{"$ne":0}}},
{$project:{
_id:0,
name:1,
density: {$divide: ["$population","$area"]}
}}
])
Population in millions
Show the name and population in millions for the countries of the continent South America. Divide the population by 1000000 to get population in millions.
db.world.aggregate([
{$match:{
}},
{$project:{
_id:0,
name:1
}}
])
db.world.aggregate([{"$match":{"continent":{"$eq":"South America"}}},{"$project":{"_id":0,"name":1,"population":{"$divide":["$population",1000000]}}}])
Population density
Show the name and population density for France, Germany, and Italy
db.world.aggregate([
{$match:{
name: {$in:['United Kingdom','United States','Brazil']},
population: {$ne: null},
area: {$ne: 0}
}},
{$project:{
_id:0,
name:1
}}
])
db.world.aggregate([{"$match":{"name":{"$in":['France','Germany','Italy']},"population":{"$ne":null},"area":{"$ne":0}}},{"$project":{"_id":0,"name":1,"population density":{"$divide":["$population","$area"]}}}])
Continents by area
Order the continents by area from most to least.
db.world.aggregate([
{$group:{
_id:"$name",
area:{$max: "$area"}
}},
{$sort:{
area: -1
}},
{$project:{
_id:1,
area:1
}}
])
db.world.aggregate([
{"$group":{
"_id":"$continent",
"area":{"$sum": "$area"}
}},
{"$sort":{
"area": -1
}},
{"$project":{
"_id":1,
"area":1
}}
])
Big Continents
Show the only two continents with total area greater than 25000000 and then sort from largest to smallest.
db.world.aggregate([
{$match:{
continent:"North America"
}},
{$project:{
_id:0,
name:1
}}
])
db.world.aggregate([
{$group:{
_id:"$continent",
area:{$sum: "$area"}
}},
{$sort:{
area: -1
}},
{$match:{
area:{$gt:25000000}
}}
])
First and last country by continent
For each continent show the first and last country alphabetically like this:
{ "_id" : "Africa", "from" : "Algeria", "to" : "Zimbabwe" }
{ "_id" : "Asia", "from" : "Afghanistan", "to" : "Yemen" }
{ "_id" : "Caribbean", "from" : "Antigua and Barbuda", "to" : "Trinidad and Tobago" }
{ "_id" : "Eurasia", "from" : "Armenia", "to" : "Russia" }
{ "_id" : "Europe", "from" : "Albania", "to" : "Vatican City" }
{ "_id" : "North America", "from" : "Belize", "to" : "United States" }
{ "_id" : "Oceania", "from" : "Australia", "to" : "Vanuatu" }
{ "_id" : "South America", "from" : "Argentina", "to" : "Venezuela" }
db.world.aggregate([
{$group:{
_id:"$continent"
}},
{$sort:{
_id:1
}}
])
db.world.aggregate([
{$sort:{name:1}},
{$group:{
_id:'$continent',
from:{$first:'$name'},
to:{$last:'$name'}
},
},
{$sort:{_id:1}}
])
Countries beginning with...
Group countries according to the first letter of the name. As shown. Only give "U" through to "Z".
You will need to use the $substr function and the $push aggregate function.
{ "_id" : "U", "list" : [ "Uganda", "Ukraine", "United Arab Emirates", "United Kingdom", "United States", "Uruguay", "Uzbekistan" ] }
{ "_id" : "V", "list" : [ "Vanuatu", "Vatican City", "Venezuela", "Vietnam" ] }
{ "_id" : "Y", "list" : [ "Yemen" ] }
{ "_id" : "Z", "list" : [ "Zambia", "Zimbabwe" ] }
db.world.aggregate([
{$project:{_id:'$name',
startsWith:{$substr:['$name',0,1]}}},
{$match:{_id:{$gte:'U'}}},
{$sort:{_id:1}}
])
db.world.aggregate([
{$group:{
_id:{ $substr:['$name',0,1] },
list:{$push:'$name'}
}},
{$match:{_id:{$gte:'U'}}},
{$sort:{_id:1}}
])
Harder Questions
Messing with continent names
Combine North America and South America to America, and then list the continents by area. Biggest first.
db.world.aggregate([
{$group:{
_id:{
$cond: [{$eq:["$continent","North America"]},"America",
{$cond: [{$eq:["$continent","Asia"]},"The East","$continent"]}]
},
area:{$sum: "$area"}
}},
{$sort:{
area: -1
}},
{$project:{
_id:1,
area:1
}}
])
db.world.aggregate([{"$group":{"_id":{"$cond":[{"$eq":["$continent","South America"]},"America",{"$cond":[{"$eq":["$continent","North America"]},"America","$continent"]}]},"area":{"$sum":"$area"}}},{"$sort":{"area":-1}},{"$project":{"_id":1,"area":1}}])
Messing with continent names 2
Show the name and the continent for countries beginning with N - but replace the continent Oceania with Australasia.
db.world.aggregate([
{$match:{
name:{$regex:"^N"}
}},
{$project:{
_id:0,
name:1
}}
])
db.world.aggregate([{"$match":{"name":{"$regex":"^N"}}},{"$project":{"_id":0,"name":1,"continent":{"$cond":[{"$eq":["$continent","Oceania"]},"Australasia","$continent"]}}}])
Messing with continent names 3
Show the name and the continent but:
substitute Eurasia for Europe and Asia.
substitute America - for each country in North America or South America or Caribbean.
Only show countries beginning with A or B
If you're struggling you may want to experiment with $and,$or, etc.
db.world.aggregate([
{$match:{
name:{$regex:"^A|^B"}
}},
{$project:{
_id:0,
name:1,
continent: {
$cond: [{
$or:[
{$eq:["$continent","Europe"]},
{$eq:["$continent","Asia"]}
]},"Eurasia",{
$cond: [
{$or:[
{$eq:["$continent","North America"]},
{$eq:["$continent","South America"]},
{$eq:["$continent","Caribbean"]}
]},"America","$continent"]}
]}
}}
])
Messing with continent names 4
Put the continents right...
Oceania becomes Australasia
Countries in Eurasia and Turkey go to Europe/Asia
Caribbean islands starting with 'B' go to North America, other Caribbean islands go to South America
Show the name, the original continent and the new continent of all countries.
db.world.aggregate([
{"$project":{
"_id":0,
"name":1,
"original": "$continent",
"new": {
"$cond": [
{"$or":[
{"$eq":["$continent","Eurasia"]},
{"$eq":["$name","Turkey"]}
]},"Europe/Asia",{
"$cond":[
{"$eq":["$continent","Oceania"]},"Australasia",{
"$cond":[
{"$and":[
{"$eq":["$continent","Caribbean"]},
{"$eq":[{"$substr":["$name",0,1]}, "B"]}
]},"North America",{
"$cond":[
{"$and":[
{"$eq":["$continent","Caribbean"]},
{"$ne":[{"$substr":["$name",0,1]}, "B"]}
]},"South America","$continent"
]
}
]
}
]
}
]
}
}}
])